Author: admin

Problem Statement

A for loop is a programming language statement which allows code to be repeatedly executed.

The syntax for this is

for ( <expression_1> ; <expression_2> ; <expression_3> )
    <statement>

• expression_1 is used for intializing variables which are generally used for controlling terminating flag for the loop.
• expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
• expression_3 is generally used to update the flags/variables.

A sample loop will be

for(int i = 0; i < 10; i++) {
    ...
}

Input Format

You will be given two positive integers, a and b (a≤b), separated by a newline.

Output Format

For each integer n∈[a,b] (so all numbers in that range):

• If 1≤n≤9, then print the English representation of it. That is “one” for 1, “two” for 2, and so on.
• Else if n>9 and it is even, then print “even”.
• Else if n>9 and it is odd, then print “odd”.

Note: [a,b] represents the interval, i.e., [a,b]={x∈Z| a≤x≤b}={a, a+1,…,b}

Sample Input

8
11

Sample Output

eight
nine
even
odd

Problem Statement

if and else are two of the most heavily used conditionals in C/C++. They are used to execute zero or one statement among many statements.

They are be used in the following three ways.

1. if: It is used to execute a statement, given the condition is true.

   if(condition) {
       ...
   }
   

2. if – else: It is used to execute exactly one of the two statements.

   if(first condition) {
       ...
   }
   else {
       ...
   }
   

3. if – else if – else: It is used to execute one of the multiple statements.

   if(first condition) {
       ...
   }
   else if(second condition) {
       ...
   }
   .
   .
   .
   else if((n-1)'th condition) {
   
   }
   else {
       ...
   }
   

You are given a positive integer, n,:

• If 1≤n≤9, then print the English representation of it. That is “one” for 1, “two” for 2, and so on.
• Otherwise print “Greater than 9” (without quotes).

Input Format

Input will contain only one integer, n.

Output Format

Print the output as described above.

Sample Input

5

Sample Output

five

Sample Input #01

8

Sample Output #01

eight

Sample Input #02

44

Sample Output #02

Greater than 9

Problem Statement

A pointer in C is a way to share a memory address among different contexts (primarily functions). They are primarily used whenever a function needs to modify the content of a variable, of which it doesn’t have ownership.

In order to access the memory address of a variable, val, we need to prepend it with & sign. E.g., ‘‘&val“ returns the memory address of val.

This memory address is assigned to a pointer and can be shared among various functions. E.g. int∗p=&val will assign the memory address of val to pointer p. To access the content of the memory to which the pointer points, prepend it with a ‘‘∗“. For example, ∗p will return the value reflected by val and any modification to it will be reflected at the source (val).

void increment(int *v) {
    (*v)++;
}

int main() {
    int a;
    scanf("%d", &a);
    increment(&a);
    printf("%d", a);
    return 0;
}  

You have to complete the function void update(int *a,int *b), which reads two integers as argument, and sets a with the sum of them, and b with the absolute difference of them.

• a′=a+b
• b′=|a−b|

Input Format

Input will contain two integers, a and b, separated by a newline.

Output Format

You have to print the updated value of a and b, on two different lines.
P.S.: Input/ouput will be automatically handled. You only have to complete the void update(int *a,int *b) function.

Sample Input

4
5

Sample Output

9
1

Explanation

• a′=4+5=9
• b′=|4−5|=1