Strings

Problem Statement

C++ provides a nice alternative data type to manipulate strings, and the data type is conveniently called string. Some of its widely used features are the following:

  • Declaration: 
    string a = "abc";
  • Size: 
    int len = a.size();
  • Concatenate two strings: 
    string a = "abc";
string b = "def";
string c = a + b; // c = "abcdef".
  • Assessing ith element: 
    string s = "abc";
char   c0 = s[0];   // c0 = 'a'
char   c1 = s[1];   // c1 = 'b'
char   c2 = s[2];   // c2 = 'c'

s[0] = 'z';         // s = "zbc"

P.S.: We will use cin/cout to read/write a string.

Input Format

You are given two strings, a and b, separated by a new line. Each string will consist of lower case Latin characters (‘a’-‘z’).

Output Format

In the first line print two space-separated integers, representing the length of a and b respectively.
In the second line print the string produced by concatenating a and b (a+b).
In the third line print two space-separated strings, a′ and b′. a′ and b′ are the same as a and b, respectively, except that their first characters are swapped.

Sample Input

abcd
ef

Sample Output

4 2
abcdef
ebcd af

Explanation

  • a=‘‘abcd“
  • b=‘‘ef“
  • |a|=4
  • |b|=2
  • a+b=‘‘abcdef“
  • a′=‘‘ebcd“
  • b′=‘‘af“

Solution

  
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
#include <string>
using namespace std;

int main() {
   // Complete the program
    string a,b;
    cin>>a>>b;
    cout<<a.size()<<" "<<b.size()<<endl;
    cout<<a+b<<endl;
    char t=a[0];
    a[0]=b[0];
    b[0]=t;
    cout<<a<<" "<<b;
    return 0;
}

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