For Loop

Problem Statement

A for loop is a programming language statement which allows code to be repeatedly executed.

The syntax for this is

for ( <expression_1> ; <expression_2> ; <expression_3> )
    <statement>
  • expression_1 is used for intializing variables which are generally used for controlling terminating flag for the loop.
  • expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
  • expression_3 is generally used to update the flags/variables.

A sample loop will be

for(int i = 0; i < 10; i++) {
    ...
}

Input Format

You will be given two positive integers, a and b (a≤b), separated by a newline.

Output Format

For each integer n∈[a,b] (so all numbers in that range):

  • If 1≤n≤9, then print the English representation of it. That is “one” for 1, “two” for 2, and so on.
  • Else if n>9 and it is even, then print “even”.
  • Else if n>9 and it is odd, then print “odd”.

Note: [a,b] represents the interval, i.e., [a,b]={x∈Z| a≤x≤b}={a, a+1,…,b}

Sample Input

8
11

Sample Output

eight
nine
even
odd

Solution

  
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

int main() {
    // Complete the code.
    int a,b;
    cin>>a>>b;
    for(int n=a;n<=b;n++)
    {
     if(n>9)
       {
          if(n%2==0)
              cout<<"even"<<endl;
           else cout<<"odd"<<endl;
       }
    else if(n==9)
        cout<<"nine"<<endl;
    else if(n==1)
        cout<<"one"<<endl;
    else if(n==2)
        cout<<"two"<<endl;  
    else if(n==3)
        cout<<"three"<<endl;        
    else if(n==4)
        cout<<"four"<<endl; 
    else if(n==5)
        cout<<"five"<<endl;
    else if(n==6)
        cout<<"six"<<endl;
    else if(n==7)
        cout<<"seven"<<endl;      
    else
        cout<<"eight"<<endl; 
     
    }
    return 0;
}

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